8x^2+20=16x-8

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Solution for 8x^2+20=16x-8 equation: 



8x^2+20=16x-8

We move all terms to the left:

8x^2+20-(16x-8)=0

We get rid of parentheses

8x^2-16x+8+20=0

We add all the numbers together, and all the variables

8x^2-16x+28=0

a = 8; b = -16; c = +28;
Δ = b2-4ac
Δ = -162-4·8·28
Δ = -640
Delta is less than zero, so there is no solution for the equation

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